Add Two Numbers
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example 1:
Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.
Example 2:
Input: l1 = [0], l2 = [0]
Output: [0]
Example 3:
Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]
Constraints:
- The number of nodes in each linked list is in the range
[1, 100]
. 0 <= Node.val <= 9
- It is guaranteed that the list represents a number that does not have leading zeros.
solution:
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var addTwoNumbers = function(l1, l2) {
let result = new ListNode();
let aboveTen = 0;
let arr = [];
let currentNode1=l1 ;
let currentNode2=l2;
do {
let a = 0;
if(currentNode1 && currentNode1.val){
a = currentNode1.val;
}
let b = 0;
if(currentNode2 && currentNode2.val){
b = currentNode2.val;
}
if(currentNode1){
currentNode1 = currentNode1.next;
}
if(currentNode2){
currentNode2 = currentNode2.next;
}
arr[arr.length]=(a+b+aboveTen)%10;
aboveTen = (a+b+aboveTen)>=10?1:0;
}while((currentNode1 && currentNode1.val!=null) || (currentNode2 && currentNode2.val!=null) );
if(aboveTen>0){
arr[arr.length]=aboveTen;
}
return generateNode(0,arr);
};
function generateNode(i, arr){
if (i>=arr.length)
{
return null;
}
let node = new ListNode();
node.val=arr[i];
node.next = generateNode(++i,arr)
return node;
}